![]() The displacement is directly affected by the vibration frequency. This means when using the same motor on the two objects, the vibration amplitude would feel much smaller in the heavy object – even though the motor has the same force.Īnother aspect of the motor is the vibration frequency: As you can imagine, a much heavier object would require more force to generate the same acceleration as a small and light object. We can see that the vibration force of the motor doesn’t take the target mass into consideration. Where \(F\) is the force, \(m\) is the mass of the eccentric mass on the motor (not the whole system), \(r\) is the eccentricity of the eccentric mass, and \( \omega \) is the frequency. The force of a vibration motor is governed by the equation: This helps us plot our Typical Performance Characteristics graph. We measure the vibration amplitude by mounting the motor on a known target mass and reading the results from an accelerometer. Therefore we are interested in the whole system (motor + target mass). ![]() Vibration motors are not used on their own – they’re attached to a product/device/piece of equipment that is intended to vibrate. But why do we express the vibration amplitude as acceleration (G) instead of a force (N) or the displacement (mm)? Why not use Displacement (mm) or Force (N)? What we feel as vibrations are simply the object being repeatedly displaced and a very high frequency. It leaves some of our customers with the question exactly what is G? Our vibration motors and linear resonant actuators use the unit G to describe their vibration amplitude. But why do we express the vibration amplitude as acceleration (G) instead of a force (N) or the displacement (mm)? Measuring Vibration in G Well, 1 G is equal to the acceleration from gravity: ![]() Our vibration motors and linear resonant actuators use the unit G to describe their vibration amplitude. Those looking for the Quick Vibe Estimator will find the tool in AB-031: Vibration Motor Calculators – ERMs and LRAs ![]()
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